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What is the average kinetic energy per gram (in cal/g) of a sample of CH4 gas at 47°C?

1. 960
2. 60
3. 249.42
4. 2.463

Correct answer: 60

Solution

KE per mole = (3/2)RT = 1.5 * 8.314 * 320 = 3990.72 J/mol. Per gram = 3990.72/16 = 249.42 J/g. Converting: 249.42/4.184 ≈ 59.6 cal/g ≈ 60 cal/g. Wait — 249.42 J/g / 4.184 ≈ 59.6 cal/g, so the answer is approximately 60 cal/g.

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