Exams › JEE Advanced › Chemistry

What form does the van der Waals equation take for a gas where intermolecular attractions are neglected, but the finite volume of molecules is considered?

1. P(V + nb) = nRT
2. P(V - nb) = nRT
3. P(V) = nRT
4. P(V) = nRT - an²/V

Correct answer: P(V - nb) = nRT

Solution

When intermolecular attractions are neglected but the finite volume of molecules is considered, the van der Waals equation reduces to P(V - nb) = nRT, where 'b' accounts for the volume occupied by the gas molecules.

Related JEE Advanced Chemistry questions

• In the van der Waals equation, what does the term (a)/(V²) signify?
• A sealed container holds 10 g of an ideal gas X at 300 K, exerting a pressure of 2 atm. When 80 g of a different ideal gas Y is introduced at the same temperature, the pressure rises to 6 atm. What is the ratio of the root mean square speeds of X and Y at 300 K?
• The compressibility factor Z of a Van der Waals gas is 0.5 at 27 degrees C and 24 atm. Given b = 0.10 L/mol and R = 0.08 L-atm/(K-mol), find the Van der Waals constant a in atm-L²/mol².
• Identify the INCORRECT statement about real gases:
• Which combination of conditions is most favourable for the melting of ice into water?
• Which of the following statements about ideal gases and kinetic theory are incorrect?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →