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A sample of 80 g of a gas SOx occupies 14 litres at 2 atm pressure and 273 K. Using R = 0.0821 L·atm/(K·mol), determine the value of x.

1. 3
2. 2
3. 1
4. None of these

Correct answer: 2

Solution

From PV = nRT: n = (2*14)/(0.0821*273) = 28/22.41 = 1.249 mol. Molar mass = 80/1.249 = 64 g/mol. Solving 32 + 16x = 64 gives x = 2, identifying the gas as SO2.

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