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1 mole of an ideal gas is compressed from state A to state B along the path shown on a P-V graph. Calculate the work done during this compression. [Given: 1 L-atm = 100 J, ln 2 = 0.7, ln 2.8 = 1.03]

1. W = 186.67 J
2. W = -784 J
3. W = 784 J
4. W = 53.57 J

Correct answer: W = -784 J

Solution

For isothermal compression of 1 mole of ideal gas from V1 to V2, W = -nRT*ln(V2/V1) = nRT*ln(V1/V2). Using ln(2.8) = 1.03 and nRT such that the magnitude is 7.84 L-atm = 784 J, with compression (V decreases), work done BY gas = -784 J.

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