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A gas initially at 5.0 atm pressure is heated from 0 degC to 546 degC while simultaneously being compressed to one-third of its original volume. What is the final pressure of the gas?
- 10 atm
- 30 atm
- 45 atm
- 5 atm
Correct answer: 45 atm
Solution
Using P1*V1/T1 = P2*V2/T2: P2 = P1*(V1/V2)*(T2/T1) = 5*(3)*(819/273) = 5*3*3 = 45 atm.
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