In an adsorption experiment, the graph of log(x/m) versus log(P) is linear with a slope of 45 degrees and a y-intercept of 0.3010. Calculate the mass of gas adsorbed per gram of charcoal at a pressure of 3 bar. (Given: log 2 = 0.3010)

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Accepted Answer

6 g. The Freundlich adsorption isotherm in log form: log(x/m) = log k + (1/n) log P. Slope = 1/n = tan 45 deg = 1, so n = 1. Intercept = log k = 0.3010 => k = 2. Then x/m = k * P = 2 * 3 = 6 g/g.

In an adsorption experiment, the graph of log(x/m) versus log(P) is linear with a slope of 45 degrees and a y-intercept of 0.3010. Calculate the mass of gas adsorbed per gram of charcoal at a pressure of 3 bar. (Given: log 2 = 0.3010)

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