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For the reaction A + B -> product, the following experimental data is observed: Exp 1: [A]0 = 0.02 mol/L, [B]0 = 0.03 mol/L, Rate = 4 * 10⁻³ mol/L/s Exp 2: [A]0 = 0.04 mol/L, [B]0 = 0.06 mol/L, Rate = 1.6 * 10⁻² mol/L/s Exp 3: [A]0 = 0.01 mol/L, [B]0 = 0.06 mol/L, Rate = 4 * 10⁻³ mol/L/s Which of the following statements is/are correct?
- The given reaction may be an elementary reaction
- The value of the rate constant is 6.67 mol⁻¹ L s⁻¹
- The given reaction may be a complex (multi-step) reaction
- If the volume of the container in experiment 1 is doubled, the rate becomes 10⁻³ mol/L/s
Correct answer: The value of the rate constant is 6.67 mol⁻¹ L s⁻¹
Solution
Comparing Exp 1 and Exp 3: [B] is doubled from 0.03 to 0.06 but [A] is halved from 0.02 to 0.01; rate stays the same at 4e-3. Comparing Exp 1 and Exp 2: both [A] and [B] are doubled; rate increases 4 times (from 4e-3 to 1.6e-2). If rate = k[A]^x[B]^y, then 4 = 2^x * 2^y. Separately, from Exp1 vs Exp3: doubling [B] and halving [A] gives rate ratio 1, so (1/2)^x * 2^y = 1 => y = x. Then 4 = 2^(2x) => x = 1, y = 1. Rate = k[A][B], second order overall. From Exp 1: k = 4e-3 / (0.02 * 0.03) = 6.67 mol⁻¹ L s⁻¹. An elementary A+B reaction would be second-order, consistent; it could also be a complex reaction with the same rate law. Doubling volume halves concentrations: new rate = 6.67 * 0.01 * 0.015 = 10⁻³ mol/L/s.
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