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In a rigid 1-litre closed vessel, SO3 decomposes according to: SO3(g) -> SO2(g) + (1/2)O2(g). At t = 20 min, the rate of appearance of O2 is found to be 20 g per litre per minute. If d[SO3]/dt at that instant equals -x/3 g per litre per second, find the value of x. (Atomic mass: S = 32, O = 16)

1. 3
2. 4
3. 5
4. 6

Correct answer: 5

Solution

Rate of O2 appearance in mol/L/s = (20/32)/60 = 1/96 mol/L/s. By stoichiometry, -d[SO3]/dt = 2 * (1/96) = 1/48 mol/L/s = 80/48 = 5/3 g/L/s, so x = 5.

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