Exams › JEE Advanced › Chemistry
Correct answer: Z > 1
At high pressure, intermolecular distances are small and repulsive interactions dominate. The van der Waals compressibility factor simplifies to Z approximately 1 + Pb/(RT), which is greater than 1 since b > 0. Option A (Z > 1) and options C (Z = 1 + Pb/RT) and D (repulsive forces dominant) are all correct. Option B (with -a term) applies at low pressure / high temperature, not high pressure.