The uncertainty in momentum of an electron is 1 * 10⁻¹⁸ g cm s⁻¹. Given that the mass of an electron is 9 * 10⁻²⁸ g, what is the minimum uncertainty in its velocity?

Question

Accepted Answer

1 * 10⁹ cm s⁻¹. By Newton's second law definition p = mv, uncertainty in velocity delta_v = deltaₚ / m. delta_v = (1*10⁻¹⁸ g cm s⁻¹) / (9*10⁻²⁸ g) = (1/9)*10¹⁰ ≈ 1.11*10⁹ cm s⁻¹, which rounds to 1*10⁹ cm s⁻¹.

The uncertainty in momentum of an electron is 1 * 10⁻¹⁸ g cm s⁻¹. Given that the mass of an electron is 9 * 10⁻²⁸ g, what is the minimum uncertainty in its velocity?

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