Exams › JEE Advanced › Chemistry
Correct answer: 10, 1
For l=4 (g subshell) there are 2l+1 = 9 orbitals. Maximum spin multiplicity occurs with 9 unpaired parallel electrons: S=9/2, multiplicity = 2S+1 = 10. Lowest multiplicity (all paired or empty) is 1. So highest and lowest are 10 and 1, not 9 and 1.