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Match the species in Column I with their correct properties or uses in Column II. Column I: A. H (atomic hydrogen) B. H2 (dihydrogen) C. H2O (water) D. H2O2 (hydrogen peroxide) Column II: (i) Known commercially as perhydrol (ii) Can be reduced by NaH to give dihydrogen (iii) Used in the catalytic hydrogenation of alkenes (iv) Used in cutting and welding of metals

1. A -> iv; B -> iii; C -> ii; D -> i
2. A -> ii; B -> iv; C -> ii; D -> i
3. A -> ii; B -> iv; C -> iii; D -> i
4. A -> iii; B -> ii; C -> iv; D -> i

Correct answer: A -> ii; B -> iv; C -> iii; D -> i

Solution

D -> i: H2O2 30% solution is called perhydrol. A -> ii: Atomic hydrogen (nascent H) acts as a strong reducing agent; NaH + H2O -> NaOH + H2, meaning H2O is reduced by NaH. So C -> ii. B -> iv: Oxyhydrogen flame uses H2 for cutting/welding. B -> iii: H2 is used in hydrogenation of alkenes. This creates a conflict. Actually for matching: A=atomic H, B=H2, C=H2O, D=H2O2. (iv) cutting/welding uses oxyhydrogen or atomic-H torch -> both B and A could apply. Atomic hydrogen welding uses A. So A->iv, B->iii (hydrogenation), C->ii (NaH reduces H2O to H2), D->i. That is option A: A->iv; B->iii; C->ii; D->i. But option A has C->ii appearing twice (typo in option B). Option A: A->iv; B->iii; C->ii; D->i. Let us verify: NaH + H2O -> NaOH + H2 (H2O is being reduced? No, NaH is the reducing agent, H in NaH goes from -1 to 0, water's H goes from +1 to 0 as well. So H2O acts as oxidizing agent here). C->ii is valid. A->iv: atomic hydrogen torch is used for welding metals. B->iii: H2 used for hydrogenation. D->i: perhydrol. Answer = option A.

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