Exams › JEE Advanced › Chemistry
Correct answer: P -> 1,3,4; Q -> 1,2,4; R -> 1,2,4; S -> 1,3,4
P (Free volume): V_f = V - b. Here b depends on molecular radius (4) and is specific to the gas (1); V_f changes with volume/pressure (3). So P -> 1, 3, 4. Q (Critical temperature): T_c = 8a/(27Rb); a and b are gas-specific, so T_c depends on gas nature (1), is constant for a given gas (2), and depends on molecular size via b (4). So Q -> 1, 2, 4. R (Boyle temperature): T_B = a/(Rb); same reasoning: R -> 1, 2, 4. S (Compressibility factor at high P): Z ≈ 1 + Pb/(RT); for a given gas (fixed b and T), Z depends on P (3) and on gas nature/radius (1 and 4 via b). So S -> 1, 3, 4.