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Which of the following are disproportionation reactions? (a) 2 Cu+ -> Cu^(2+) + Cu (b) 3 MnO4^(2-) + 4 H+ -> 2 MnO4^(-) + MnO2 + 2 H2O (c) 2 KMnO4 -> K2MnO4 + MnO2 + O2 (d) 2 MnO4^(-) + 3 Mn^(2+) + 2 H2O -> 5 MnO2 + 4 H+
- a and b only
- a, b, and c only
- b, c, and d only
- a and d only
Correct answer: a and b only
Solution
Disproportionation: same element/atom oxidized and reduced simultaneously. (a) Cu+ (+1) -> Cu²+ (+2, oxidized) + Cu (0, reduced). YES. (b) MnO4²- (Mn is +6) -> MnO4⁻ (Mn +7, oxidized) + MnO2 (Mn +4, reduced). YES. (c) 2KMnO4 -> K2MnO4 + MnO2 + O2: Mn goes from +7 in KMnO4 to +6 in K2MnO4 (reduced) and +4 in MnO2 (further reduced). Oxygen in O2 comes from decomposition but Mn only gets reduced - there is also oxidation component. Actually Mn+7 -> Mn+6 and Mn+4 are both reductions; the oxidation is of O²- to O2 (0). So disproportionation involves different elements (Mn reduced, O oxidized). This is NOT a disproportionation of Mn alone; it could be classified as disproportionation of the compound but Mn itself doesn't get oxidized. NOT disproportionation in strict sense. (d) MnO4⁻ (+7) + Mn²+ (+2) -> MnO2 (+4): this is comproportionation (two different oxidation states of Mn come together). NOT disproportionation. Answer: a and b.
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