The coagulation of 200 mL of a positively charged colloid required the addition of 0.73 g of HCl. What is the flocculation value of HCl for this colloid (in millimoles per litre)?

Question

Accepted Answer

100. The flocculation value is the number of millimoles of electrolyte required to coagulate one litre of the colloid. Moles of HCl = 0.73/36.5 = 0.02 mol = 20 mmol. Volume of colloid = 200 mL = 0.2 L. Flocculation value = 20/0.2 = 100 mmol/L.

The coagulation of 200 mL of a positively charged colloid required the addition of 0.73 g of HCl. What is the flocculation value of HCl for this colloid (in millimoles per litre)?

Solution

Related JEE Advanced Chemistry questions