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A 280 mL sample of aqueous H2O2 solution was completely consumed by 100 mL of 0.1 M KMnO4 in acidic medium. Using the reaction: 2KMnO4 + 3H2SO4 + 5H2O2 -> K2SO4 + 2MnSO4 + 3H2O + 5O2, determine the volume strength of the H2O2 solution.
- 2 volumes
- 4 volumes
- 5.5 volumes
- 8 volumes
Correct answer: 2 volumes
Solution
From stoichiometry 2 mol KMnO4 reacts with 5 mol H2O2. Moles of KMnO4 = 0.01, so moles H2O2 = 0.025. Molarity = 0.025/0.280 = 0.08929 M. Volume strength = (vol O2 at STP produced per vol solution) = (0.025 * 22400 mL) / 280 mL = 560/280 = 2.0 volumes.
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