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7 persons A-G in row. Flowers 21-27. A 4 left of C; both not at extremes. F at pos7. C not even flowers. C+B=46. F+C=47, F adjacent C. Person with 21 flowers at pos1. G=multiple of 3&9, adjacent C, opposite direction. E>B<C in flowers, E faces south. More than 3 face north. Extreme ends same direction. Sum of flowers of which two is 53?

1. G & B
2. G & D
3. C & B
4. C & E

Correct answer: G & D

Solution

A=pos2,C=pos6. C=25(odd),F=22,B=21(pos1,21 flowers✓). G=27(multiple of 9), adjacent C(pos6)→pos5. A adjacent to 26-flower person → pos3=D(26). Remaining: A and E have 23,24. G(27)+D(26)=53.

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