StreakPeaked· Practice

ExamsIBPS POReasoning

Direction: Read the following information carefully and answer the question. Eight persons P, Q, R, S, T, U, V, and W were born in different years 1982, 1986, 1990, 1993, 1996, 1999, 2000, and 2009, but not necessarily in the same order. It is assumed that all of them were born on the same date in different years. All age calculations are done taking the base year as 2021. - Two persons were born between R and Q. - The age of R is a perfect square of 5. - One person was born between Q and W. - Three persons were born between W and V. - P is younger than V and elder than R. - The age of P is a multiple of 7. - The sum of V's age and S's age is 56. - The difference between the age of S and the age of T is 18. In which year was P born?

  1. 1999
  2. 1996
  3. 1993
  4. 2000

Correct answer: 1993

Solution

Since the base year is 2021, the possible ages are 39, 35, 31, 28, 25, 22, 21, and 12. The age of R is a perfect square of 5, so R must be 25 years old, i.e. born in 1996. Using the spacing conditions and the sum/difference clues, the only consistent placement gives P as 28 years old, so P was born in 1993.

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