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Ten persons attend a seminar in two different months, i.e., June and July, in two consecutive weeks. Each month has one week. The first week starts from Monday and ends on Sunday. P attends the seminar on a double-digit odd prime date in the given month. No two adjacent days are vacant. R attends the seminar two days before P. One person attends the seminar between P and I, who attends the seminar in the month having an odd number of days. I and Q attend the seminar on the same day. J attends the seminar after Q and before R on an even-numbered date. As many persons attend the seminar between J and R as between I and L. L attends the seminar on an even-numbered date. O attends the seminar three days after L. L attends after I. No one attends the seminar between O and K, who attends the seminar on an odd-numbered date. As many persons attend after K as before Q. M attends the seminar in the month having the maximum number of days. N attends before Q. Which among the following pairs of persons attend the seminar on the same day?
- N, O
- I, K
- L, R
- I, L
Correct answer: L, R
Solution
The clues force a unique schedule across the two months. Since R is two days before P and J lies between Q and R, the arrangement locks several dates together; further, I and Q are on the same day and L is placed so that O is three days after L. In the final arrangement, L and R end up attending on the same day.
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