Exams › IBPS PO › Reasoning
Eight people S, T, U, V, W, X, Y, and Z were born in different years: 1947, 1953, 1958, 1967, 1974, 1982, 1994, and 2002, but not necessarily in the same order. The date and month of birth of all these persons are the same. The calculation is done with respect to the year 2017, assuming the month and date to be the same. The difference between the ages of S and U is a perfect cube. V's age is a multiple of 5, but V is not the oldest person. The difference between the ages of V and S is equal to the age of V. The age of X is equal to the difference between the ages of V and Y. T is the second youngest among all of them. The difference between the ages of T and Z is a perfect square. What is the age of Z?
- 64 year
- 59 year
- 43 year
- 23 year
Correct answer: 59 year
Solution
The ages in 2017 are 15, 23, 35, 35, 43, 50, 60, and 70? Wait, using the given years, the ages are 70, 64, 59, 50, 43, 35, 23, and 15. Since V is a multiple of 5 and not oldest, V can be 50 or 35 or 15, but the difference condition with S fixes V as 35 and S as 70. Then X equals the difference between V and Y, and T is second youngest, so T is 23. The only age that differs from 23 by a perfect square among the remaining ages is 59, since 59 - 23 = 36. Therefore, Z is 59 years old.
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