Exams › IBPS PO › Reasoning
Directions: A number arrangement machine, when given an input line of numbers, rearranges them following a particular rule in each step. The following is an illustration of the input and rearrangement. Input: 35 47 59 39 68 Step I: 332 443 554 336 662 Step II: 331 441 551 333 664 Step III: 331 333 441 551 664 Step V: 14 18 18 22 48 Step V is the last step of the arrangement. As per the rule followed in the above steps, find the appropriate step for the given input: Input: 19 27 78 48 57 What is the sum of the numbers which is 3rd from the left in Step III and 4th from the right in the final step?
- 447
- 454
- 443
- 466
Correct answer: 454
Solution
The machine applies a fixed transformation to each number and then rearranges the results in later steps. For the given input, after following the same pattern, the 3rd number from the left in Step III and the 4th number from the right in the final step are obtained and their sum is 454. The correct option is therefore 454.
Related IBPS PO Reasoning questions
- Directions (1–4): Study the given information and answer the questions. When a number arrangement machine is given an input line of numbers, it arranges them following a particular rule. The following is an illustration of an input and its rearrangement. Input: 65 18 41 53 72 34 89 26 Step 1: 195 36 123 159 144 68 267 52 Step 2: 159 159 36 303 76 335 215 Step 3: 45 45 18 0 42 45 10 Step 4: 22.5 22.5 9 0 21 22.5 5 Step IV is the last step of the above arrangement as the intended arrangement is obtained. As per the rules followed in the given steps, find the appropriate steps for the input: 25 22 93 56 17 74 39. What is the sum of the numbers at both the ends in Step III of the given arrangement?
- Directions (30-34): Study the following information carefully to answer the question. Five persons — M, N, O, P and Q — have five different ships — A, B, C, D and E — docked at five different ports — R, S, T, U and V. The information is not necessarily in the same order. N doesn’t have Ship B or Ship E. Ship B is not docked at Port S or Port U. Q doesn’t dock the ship at Port S or Port R. O doesn’t dock the ship at Port S, Port U or Port V. M, O and P don’t have Ship E. P and Ship D are not docked at Port U. P doesn’t have Ship C or Ship B. P doesn’t dock the ship at Port U or Port V. The person whose ship is docked at Port R doesn’t have Ship C or Ship A. P doesn’t dock the ship at Port R or Port S. M doesn’t dock the ship at Port S. The person whose ship is docked at Port S or Port U doesn’t have Ship D. The person whose ship is docked at Port T doesn’t have Ship D. Port R doesn’t have Ship B docked. Which ship is docked at Port T?
- Passage: Input: 376824 943875 584762 758493 843642 395648 Step I: 386925 842865 594863 657483 742632 405749 Step II: 387006 842929 594944 657547 742681 405830 Step III: 184880 721842 203694 423554 71248 4003 Step IV: 248 400 424 2064 2842 84880 Step V: 128 160 124 464 6042 48880 Step VI: 33 21 21 42 28 140 New Input: 478269 835264 712386 384561 532649 784678 What comes first to the left of the number which is third from the right end in Step III?
- Direction: Study the given information carefully and answer the following question. There are six persons, namely A, B, C, D, M and O, sitting in a row facing north, but not necessarily in the same order. All have different ages. C sits 3rd from one of the ends. D sits immediately to the left of C. O sits 2nd to the right of the one who is 6 years old. C is not 12 years old. Two persons sit between D and B, whose age is twice that of D. M sits to the right of A. The one who is 36 years old sits 3rd to the one who is 15 years old. The age of A is the sum of the ages of D and O. The age of O is 18 years. What is the age of A?
- Passage: When a word-and-number rearrangement machine is given an input line of words and numbers, it arranges them according to a rule. The following is an illustration of the input and rearrangement. Input: 7289 CLAY 2854 POUR 5941 ABLE 6217 FLIP 9723 ONUS Step I: 49398 ABLE 4963 ONUS 251050 CLAY 36326 FLIP 81832 POUR Step II: 48399 BAKF 4639 PMVR 2155 BKBX 26633 EKJO 28813 OPVQ Step III: 1221 BKF 1012 PMVR 211 KX 146 KJ 184 PVQ Step IV: 429 BFK 134 MPRV 119 KX 22 JK 2 PQV Step V: 432 130 117 20 5 Step V is the last step for the above input. Find the appropriate steps for the following input: Input: 8345 UNIT 4972 DROP 3186 EVEN 5294 SOUP 1376 PLAY In Step II, what number is immediately left of 'FUFM'?
- Passage: F 3 6 N @ 9 K T Q 5 C % 8 B # 7 D S * H 4 W L STEP I: The numbers which are immediately preceded by a symbol and immediately followed by an alphabet are arranged at the end of the series in increasing order, immediately after L. STEP II: The odd numbers which are immediately preceded by an alphabet interchange their positions with the alphabet just before them. STEP III: The alphabets which are immediately followed by a symbol are arranged in alphabetical order between H and 4 of Step II. Note: Step II is applied after Step I and Step III is applied after Step II. Question: How many alphabets are immediately preceded and immediately followed by numbers in Step II?
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