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Six persons are arranged in descending order of their weights from left to right. E is not the heaviest among all. A is heavier than F and C. F is heavier than B and D but not heavier than E. B and C are not the lightest among all. A is not just heavier than F. E is heavier than C, who is not the 3rd heaviest among all. The weight of the 2nd lightest person is 17 kg. The total weight of B and C is 44 kg. The 2nd heaviest person is twice as heavy as the 2nd lightest person. C is just lighter than F. The total weight of all the persons is 150 kg. The number of persons heavier than F is the same as the number of persons lighter than __?
- A
- C
- D
- B
Correct answer: B
Solution
The clues establish a unique descending order of weights. After placing all six persons consistently, the count of people heavier than F equals the count of people lighter than B. Therefore, B is the required person.
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