Seven persons J, K, L, M, N, O, and P are in a family. They were born in 1960, 1970, 1981, 1983, 1986, 1996, and 2007, not necessarily in the same order. The sum of the ages of L and O is 79. The age gap between O and M is the same as the age gap between L and K. O is older than M. The sum of the ages of J and N is double the age of P. M is an even number. J is not younger than N. Note: The base year is 2023 for calculating the ages of all the family members. Who is immediately younger than N?

Correct answer: K

Solution

Using 2023 as the base year, the ages are fixed and can be matched to the seven persons. The sum and difference conditions narrow the arrangement uniquely, and the person immediately younger than N comes out to be K. Therefore, K is immediately younger than N.

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