Exams › IBPS PO › Reasoning
A matrix contains 4 rows (I, II, III and IV) from top to bottom and 4 columns (I, II, III and IV) from left to right. Meaningful words will be formed only when we go left to right in a row and top to bottom in a column. Conditions: - No letters are repeated more than twice. - Alphabets are coded as A-1, B-2, C-3, D-4, E-5, F-1, G-2, H-3, I-4, ..., Y-5, Z-1. - The place values of the column and row are added to get the cell value of a particular row or column. - If a column/row has one letter, then the entire column/row should not have that letter. A 4-letter meaningful word has to be formed in each column: - In column I: positions I, II, and IV contain the letters V, A, and T respectively. - In column II: positions III and IV contain the letters H and O respectively. - In column III: position II contains the letter R. - In column IV: positions I, III, and IV contain the letters N, T, and S respectively. Question: What is the sum of the positional values of the letters in (I, IV) and (III, II), where the bracket represents (row, column)?
- 6
- 8
- 5
- 7
Correct answer: 7
Solution
The cell (I, IV) and (III, II) correspond to letters whose positional values are determined by the given coding rule. Adding those two values gives 7.
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