IBPS PO Reasoning: Puzzle Arrangement questions with solutions

Q1. Eight persons P, Q, R, S, T, A, B and U got LPG subsidies on two different dates, 3rd or 12th, in four different months, i.e. January, June, September and October, but not necessarily in the same order. T gets his subsidy on an even date in the month which has 30 days. Three persons get subsidies between A and T. P gets subsidy just before B but not in the same month. Two persons get subsidies between B and U. Q gets subsidy before S and both of them get subsidies before B. Question: On which of the following dates does P get subsidy?

1. 3rd September
2. 12th January
3. 12th June
4. 3rd October

Answer: 12th June

T must be on 12th in a 30-day month, so T is in June or September. Using the clue that three persons are between A and T and the order constraints among P, B, U, Q, and S, the only consistent arrangement places P on 12th June. Hence, P gets the subsidy on 12th June.

Q2. Read the given information carefully and answer the question. Six persons visit a place on two dates, 11 and 22, in three different months, i.e., September, October and November. They all like different colors: white, blue, pink, green, red and yellow, but not necessarily in the same order. The one who likes yellow visits three persons after L. L and S visit on the same date and in the month of even-numbered days. Two persons visit between S and R, who likes green. The number of persons who visit before R is the same as the number of persons who visit after V. The one who likes white visits just before H. No one visits between K and the one who likes blue. The one who likes red visits before the one who likes pink. Which of the following statements is/are true? I. The one who likes green is the last one to visit. II. H likes pink. III. More than two persons visit before V.

1. Only II
2. Only I and III
3. Only I and II
4. Only III

Answer: Only III

The clues force a unique relative order of visitors across months, dates, and colors. Once the positions of L, S, R, and V are fixed, statement III follows because V cannot be near the beginning. Statements I and II do not necessarily hold in the valid arrangement.

Q3. Ten people A, B, C, D, E, F, G, H, I, and J sit at two rectangular tables X and Y. Three of them like horror novels, three like thriller novels and the remaining like romance novels. Four people sit at table X and the remaining sit at table Y. The person sitting in the middle faces outside the center and the person sitting in the corner faces inside the center. People sitting at table X sit in the middle of table Y; four persons sit in the middle and four sit in the corner. Two seats are vacant at table Y. D sits at table X. J does not sit at table Y. G sits immediately left of J and neither of them likes thrillers. The one who likes romance does not sit in the middle of table Y. D likes romance and sits opposite G. E likes romance and sits at table Y. Both the immediate neighbors of E like thrillers. A sits immediately left of the one who likes thrillers. F sits third to the right of A. C sits at table X. B does not like thrillers or romance. Two persons sit between D and the one who likes thrillers. I sits 2nd to the right of a vacant seat. Vacant seats are not adjacent to each other. One of the persons who likes horror sits immediately right of the one who likes romance. After the arrangement: I. J and H change their novels. II. F and G change their novels. III. D changes his novel with the one who sits immediately left of A. IV. B and E change their place but not the novels. Note: The final arrangement is obtained after the I, III, and IV changes are done. Who are the immediate neighbors of J?

1. E and H
2. G and D
3. A and B
4. C and F

Answer: G and D

The initial arrangement places J at table X with G immediately to one side and D on the other side after the specified swaps are applied. Since only the listed exchanges are performed, J's adjacent persons in the final arrangement remain determined by the original table structure and the swap effects. Thus, the immediate neighbors of J are G and D.

Q4. Direction: Study the following information carefully and answer the questions given below. An arrangement machine, when given a particular input, rearranges it following a particular rule. The following is an illustration of the input and the steps of arrangement. Input: Lion Meat Pour Step Tear Fat Gel Pot Mud Step I: Meat Pour Step Tear inol Aft Gel Pot Mud Step II: Pour Step Tear Aemt inol Aft Egl Pot Mud Step III: Step Tear Opru Aemt inol Aft Egl Opt Mud Step IV: Tear Epst Opru Aemt inol Aft Egl Opt Dmu Step V: Aert Epst Opru Aemt inol Aft Egl Opt Dmu Step V is the last step of the rearrangement. As per the rules followed in the above steps, find out the answer to the following question for the input given below. Input: Head Pain Road Test Year Mad Red Wow Cup Which word comes exactly between 'Estt' and 'Ainp' in Step V of the given input?

1. Adm
2. Test
3. Ador
4. Aery

Answer: Ador

The machine rearranges words step by step into transformed forms based on a fixed rule. Applying the same pattern to the new input places the transformed version of 'Road' between the transformed versions of 'Test' and 'Pain'. That transformed word is 'Ador'.

Q5. Study the following information carefully to answer the given question. Seven persons get different numbers of chocolates. E gets more chocolates than at most two persons. Two persons get chocolates between E and G. E gets more chocolates than K and just less chocolates than M. The number of persons who get more chocolates than K is the same as the number of persons who get less chocolates than G. E has 3 chocolates less than J, who has chocolates equal to the smallest two-digit number. J gets more chocolates than L but does not get the highest number of chocolates. D gets 6 chocolates more than E. What is the sum of the chocolates that D, J, and E have?

1. 33
2. 20
3. 30
4. 25

Answer: 30

J has chocolates equal to the smallest two-digit number, so J = 10. Since E has 3 less than J, E = 7, and D has 6 more than E, so D = 13. Therefore, D + J + E = 13 + 10 + 7 = 30.