Study the following information carefully to answer the given question. Seven persons get different numbers of chocolates. E gets more chocolates than at most two persons. Two persons get chocolates between E and G. E gets more chocolates than K and just less chocolates than M. The number of persons who get more chocolates than K is the same as the number of persons who get less chocolates than G. E has 3 chocolates less than J, who has chocolates equal to the smallest two-digit number. J gets more chocolates than L but does not get the highest number of chocolates. D gets 6 chocolates more than E. What is the sum of the chocolates that D, J, and E have?

Correct answer: 30

Solution

J has chocolates equal to the smallest two-digit number, so J = 10. Since E has 3 less than J, E = 7, and D has 6 more than E, so D = 13. Therefore, D + J + E = 13 + 10 + 7 = 30.

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