IBPS PO Reasoning: Ordering & Ranking questions with solutions

Q1. 7 persons A,B,C,D,E,F,G. 3rd heaviest=331 lbs. 2nd lightest=189 lbs. 3 heavier than D. E>F, E>G. G>C. F not lightest. B≥G but B<A. B+C=506 lbs. What is C's weight?

1. 317 lbs
2. 175 lbs
3. 275 lbs
4. 217 lbs

Answer: 175 lbs

Chain from heaviest: A>E>B>D>G>F>C. 3rd heaviest=B=331. 2nd lightest=F=189. Lightest=C. B+C=506 → C=506-331=175 lbs. Check: F=189>C=175 ✓ (C is lightest, F is 2nd lightest ✓).

Q2. Five persons P,Q,R,S,T. Q>R, Q>S, Q<T. S<T. T is not the tallest. Who is tallest?

1. T
2. Q
3. S
4. P

Answer: P

Chain: T>Q>R and T>Q>S. T is not the tallest → someone is above T. Only P is unmentioned in comparisons → P>T. So P>T>Q>R,S. P is tallest.

Q3. 5 persons A,B,C,D,E; designations GM>DGM>AM>SO>Clerk; pens: 19,23,35,39,51. Person with prime pens is not senior most but 2 designations senior to D. C junior to D. 39-pens person just senior to E. |pens(E)-pens(C)|=4. D has 12 more pens than C. B junior to 39-pens person. Who has maximum pens?

1. B
2. A
3. D
4. Either A or D

Answer: B

D-C=12: D=35,C=23 ✓. E=C±4=19 (prime). E is 2 designations senior to D(SO=4) → E=DGM(2). 39-pens just senior to E(DGM) → 39-pens=GM=A. Remaining pens=51→B. B is junior to A(GM) ✓. Max pens: B=51.

Q4. 6 persons: Akhil, Anuj, Aakash, Anish, Arun, Ajay. Designations (senior to junior): President, VP, Director, Chairman, Manager, Clerk. Anish not senior most but senior to Ajay. 3 positions between Arun and Anish. 2 positions between Ajay and Arun; Ajay senior to Arun. Neither Aakash nor Arun is President. Akhil senior to Aakash. Anuj not junior to Anish but senior to Aakash. Arranged alphabetically, who is 5th in the list?

1. Ajay
2. Akhil
3. Anuj
4. Anish

Answer: Anuj

Derived seniority: Anuj=1(President), Anish=2(VP), Ajay=3(Director), Akhil=4(Chairman), Arun=5(Manager), Aakash=6(Clerk). Alphabetical order: Aakash,Ajay,Akhil,Anish,Anuj,Arun. 5th alphabetically = Anuj.