Exams › IBPS PO › Reasoning
5 persons A,B,C,D,E; designations GM>DGM>AM>SO>Clerk; pens: 19,23,35,39,51. Person with prime pens is not senior most but 2 designations senior to D. C junior to D. 39-pens person just senior to E. |pens(E)-pens(C)|=4. D has 12 more pens than C. B junior to 39-pens person. Who has maximum pens?
- B
- A
- D
- Either A or D
Correct answer: B
Solution
D-C=12: D=35,C=23 ✓. E=C±4=19 (prime). E is 2 designations senior to D(SO=4) → E=DGM(2). 39-pens just senior to E(DGM) → 39-pens=GM=A. Remaining pens=51→B. B is junior to A(GM) ✓. Max pens: B=51.
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