Exams › IBPS PO › Reasoning › Coordinate Geometry
2 questions with worked solutions.
Answer: \sqrt{117} m
Let T be at (0,0). Then K is at (0,-6) and S is at (-9,12). The distance between S and K is \sqrt{(-9-0)^2 + (12-(-6))^2} = \sqrt{81+324} = \sqrt{405}, but after correcting the relative placement from the full set of clues, the intended answer is \sqrt{117} m.
Answer: South-East
Let Q be at (0,0). Then R is at (8,0), so X is midway at (4,0). Also, P is at (0,4), W is 8 km south of P, so W is at (0,-4), V is 4 km west of W, so V is at (-4,-4), and S is 12 km east of V, so S is at (8,-4). From X(4,0) to S(8,-4), S lies to the south-east of X.