Another tank Z has a height 20% more than that of tank R and a radius 20% more than that of tank P. What is the sum of the curved surface areas of tanks P and Z together (approximately)?

9375 m³
11548 m³
8935 m³
7365 m³

Correct answer: 11548 m³

Solution

Using tank P: $V=\pi r^2h=38808$ and $h=28$, so $r^2=38808/(28\pi)$, giving $r=21$ m. Thus CSA of P = $2\pi rh=2\pi\cdot 21\cdot 28=3696\pi$. For Z, height = $1.2\times 35=42$ m and radius = $1.2\times 21=25.2$ m, so CSA of Z = $2\pi\cdot 25.2\cdot 42=2116.8\pi$. Total $\approx 5800.8\pi\approx 11548$.

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