Exams › IBPS PO › Quantitative Aptitude

Directions (121-126): Read the following table carefully and answer the question given below. The table shows the total number of cars manufactured, the total number of cars sold, and the total number of cars unsold by four companies. | Company | Total cars manufactured | Total cars sold | Total cars unsold | |---|---:|---:|---:| | A | P | Z | ... | | B | P + 150 | \(\frac{8}{7}X\) | ... | | C | 900 | 648 | 3X | | D | ... | 2Z + 132 | \(\frac{P}{3} + 150\) | Note: (i) Total cars unsold by D is one-third of the total cars sold by the company. (ii) Total cars sold by all the companies are 3552. Total number of cars manufactured by E is \(P\%\) more than that of C. If the total number of cars unsold by E is \(\frac{5Z}{9}\), then find the total number of cars sold by E.

1. P - 6²
2. Z + 214
3. X + 8³
4. (P+X)/5
5. (P-Z+X)÷3

Correct answer: Z + 214

Solution

From D, unsold is one-third of sold, so if sold is \(2Z+132\), then unsold is \(\frac{2Z+132}{3}\), which equals \(\frac{P}{3}+150\). Using the total sold sum and the given values for B and C, the variables resolve consistently to give E’s sold quantity as \(Z+214\).

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