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ExamsIBPS POQuantitative Aptitude

5 consecutive even numbers: first+last=24. Smallest odd=smallest_even+13. 3 consecutive odds: highest?

  1. 27
  2. 21
  3. 23
  4. 25

Correct answer: 25

Solution

Evens: n to n+8 with n+n+8=24 → n=8. Smallest even=8. Smallest odd=8+13=21. Three consecutive odd: 21,23,25. Highest=25.

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