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ExamsIBPS POQuantitative Aptitude

Series: 9 3 6 8 4 2 7 5 1 8 3 2 6 7 9 4 5 1 7 8 2 3 6 9 5. Remove all even numbers. 10th from right?

  1. 6
  2. 8
  3. 1
  4. 4

Correct answer: 1

Solution

Original: 9,3,6,8,4,2,7,5,1,8,3,2,6,7,9,4,5,1,7,8,2,3,6,9,5. Remove even (6,8,4,2,8,2,6,4,8,2,6): remaining odds=9,3,7,5,1,3,7,9,5,1,7,3,9,5 (14 numbers). 10th from right = 14-10+1=5th from left = 1.

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