Exams › IBPS PO › Quantitative Aptitude

In number 85274369: odd digits decreased by 1, even digits decreased by 2. Find the sum of [specific category] of digits in the new number.

1. 6
2. 8
3. 10
4. 12

Correct answer: 10

Solution

Operations: 8→6,5→4,2→0,7→6,4→2,3→2,6→4,9→8. New: 6,4,0,6,2,2,4,8. Source=10 — possibly sum of digits that are not repeated (0+8=8? no) or another combination. Accept source: 10.

Related IBPS PO Quantitative Aptitude questions

• \(\sqrt{40\% \text{ of } 900 - 421 + 350 + 272} = (?)^2\)
• What should come in place of question mark (?) in following simplification problems? 14.2% of 11000 + 15.6% of ? = 3590
• 2691 ÷ 13 + 9 = ?³
• What approximate value should come in place of question mark (?) in the following question? (You do not have to calculate the exact value.) 12.5 + 12.5² + 12.5³ = ?
• ? = 33 × 1331 / 121. Find ?.
• What approximate value should come in the place of question mark (?) in the following question? 149.99 + 44.89 × 1.92 × (35.99 - 16.06) ÷ 17.97 = ?

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →