Exams › IBPS PO › Quantitative Aptitude

In number 945217: add 2 to each even digit, subtract 1 from each odd digit. Find sum of digits NOT repeated in the new number.

1. 6
2. 8
3. 4
4. 5

Correct answer: 8

Solution

Odd digits: 9→8, 5→4, 1→0, 7→6. Even digits: 4→6, 2→4. New sequence: 8,6,4,4,0,6. Repeated: 6(twice), 4(twice). Non-repeated: 8, 0. Sum=8+0=8.

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