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A container has a mixture of water and acid in which water is 40% of a total mixture of 50 litres. If 30 litres of the mixture is taken out and 50 litres of another mixture of water and acid is added, and in the second mixture acid is 40%, then find the ratio of water to acid in the final mixture.
- 16:19
- 8:7
- 19:16
- 7:8
Correct answer: 19:16
Solution
Initially, water = 40% of 50 = 20 L and acid = 30 L. Removing 30 L of the original mixture removes water and acid in the same 2:3 ratio, leaving 8 L water and 12 L acid; then adding 50 L of a mixture with 40% acid adds 30 L water and 20 L acid. Final water = 38 L and acid = 32 L, so the ratio is 19:16.
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