Exams › IBPS PO › Quantitative Aptitude

What approximate value should come in place of x in the following question? \[ \left(\frac{2.99}{3.99}\right) \times \frac{3}{511.99} + 123.9\% \text{ of } 650.11 = x \]

1. 901
2. 812
3. 821
4. 832

Correct answer: 812

Solution

Approximate 2.99/3.99 ≈ 3/4 and 511.99 ≈ 512, so the first term is very small: (3/4)×(3/512) ≈ 0.004. Also, 123.9% of 650.11 ≈ 1.239 × 650 ≈ 805. Thus x is approximately 805, and among the given options the closest is 812.

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