Exams › IBPS PO › Quantitative Aptitude

What approximate value should come in place of x in the following equation? \[ \frac{1}{6} + \frac{1}{12} + \frac{1}{48} = \frac{26.99}{x} \]

1. 70
2. 80
3. 90
4. 100

Correct answer: 100

Solution

The left-hand side is \(\frac{8}{48}+\frac{4}{48}+\frac{1}{48}=\frac{13}{48}\approx 0.2708\). So \(x \approx \frac{26.99}{0.2708} \approx 99.7\), which is closest to 100.

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