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There are three vessels Y, Z, and T such that each contains a mixture of honey and water in the ratio 7:3, 3:2, and 5:3 respectively. If (x + 20) ml and 2x ml of mixture from Y, Z, and T are mixed, and the ratio of honey to water in the resultant mixture becomes 20:11, then find the value of 2.5x.

1. 100
2. 200
3. 150
4. 180

Correct answer: 200

Solution

The honey fractions are 7/10, 3/5, and 5/8 for Y, Z, and T respectively. Using the given mixed quantities and the final ratio 20:11, solving the equation gives x = 80, so 2.5x = 200.

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