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ExamsIBPS POQuantitative Aptitude

$(3.5)^2 + ?\% \text{ of } 51 = \sqrt{625}$

  1. 20
  2. 25
  3. 35
  4. 30

Correct answer: 20

Solution

We have $(3.5)^2 = 12.25$ and $\sqrt{625} = 25$. So the percentage term must be $25 - 12.25 = 12.75$. Since 12.75 is 25% of 51, the answer is 20.

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