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There are three types of coins, i.e. Gold, Silver, and Copper, in each of three bags A, B, and C. The total number of coins in all the bags is 1510. The number of coins in bag A is 580 and the total number of coins in bag B is 510. The ratio between the number of copper coins in bag A, the number of copper coins in bag B, and the number of gold coins in bag C is 3:2:4 respectively. The number of silver coins in bag B is 60 more than the number of copper coins in bag B. The number of gold coins in bag B is 25% less than the number of silver coins in bag A. The total number of gold coins in all three bags is 570. The ratio of the total number of copper coins in all three bags and the total number of silver coins in all three bags is 20:27. Find the total number of silver coins in bags B and C together.

1. 250
2. 260
3. 270
4. 280

Correct answer: 260

Solution

The data set is a multi-condition caselet involving ratios and totals across three categories. By using the copper ratio and the total in bag B, we can determine copper in B, which directly gives silver in B. Then the overall gold and copper-silver ratio conditions allow the remaining silver in bag C to be found, and the required sum becomes 260.

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