Two types of oil, A and B, are mixed in the ratio 3:2, and the total mixture is 90 litres. When one-third of the mixture was consumed, some more quantity of oil A was added, and the ratio became 2:1. The quantity of oil A added later was:

8 L
15 L
10 L
12 L

Correct answer: 12 L

Solution

Initially, A = 54 L and B = 36 L. After one-third of the 90 L mixture is consumed, 60 L remains in the same ratio, so A = 36 L and B = 24 L. If x litres of A are added, then $(36+x):24 = 2:1$, giving x = 12 L.

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