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The length of train X is equal to the sum of the lengths of trains Y and Z, while the length of train Z is 20% more than that of train Y. Train Y travels at 50 m/s and crosses a pole in 6 seconds. If train X travels at 40 m/s and crosses train Z moving in the opposite direction in 17 seconds, find the speed of train Z (in m/s).

1. 25
2. 15
3. 30
4. 20

Correct answer: 20

Solution

Train Y crosses a pole in 6 seconds at 50 m/s, so its length is 300 m. Let Y = 300 m, then Z is 20% more, so Z = 360 m, and X = 660 m. Since X and Z cross each other in opposite directions in 17 seconds, relative speed = (660 + 360)/17 = 60 m/s, so Z’s speed = 60 - 40 = 20 m/s.

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