I) $x^2 + 33x + 252 = 0$ II) $y^2 + 7y - 60 = 0$ What is the relation between $x$ and $y$?

$x \le y$
$x \ge y$
$x = y$ or relationship can't be determined
$x < y$

Correct answer: $x \le y$

Solution

The first equation factors to $(x+9)(x+28)=0$, so $x=-9$ or $x=-28$. The second factors to $(y+12)(y-5)=0$, so $y=-12$ or $y=5$. In every possible case, $x\le y$ holds.

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