Exams › IBPS PO › Quantitative Aptitude

\(\frac{3}{4}\) of \((470 + 18) + \frac{5}{6}\) of 360 = 111 \times \sqrt{?}\n What is the value of ?

1. 6
2. 16
3. 49
4. 36

Correct answer: 36

Solution

Compute the left side: \(\frac{3}{4}\times 488 = 366\) and \(\frac{5}{6}\times 360 = 300\), so total is 666. Then \(666 = 111\times \sqrt{?}\), giving \(\sqrt{?}=6\), hence \(?=36\).

Related IBPS PO Quantitative Aptitude questions

• What should come in place of the question mark in the following equation? \[ \frac{17.28 + ?}{3.6 \times 0.2} = ? \]
• $(32)^2 - 35\%$ of 580 + 14096 = ? \times 59. Find ?.
• What approximate value should come in place of the question mark (?) in the following question? 79.96% of 200.20 + 50.10 × 3.11 = ? + 25.20% of 60.13
• 272.112 + 189.98 + 84.101 = ? \times 12.89 \times 6.11
• \(\sqrt{75} \times \sqrt{300} = ?\)
• What will come in the place of the question mark (?) in the following equation? \[ \frac{5}{4}\text{ of }36 + \frac{9}{4}\text{ of }44 = ?^2 \]

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →