Exams › IBPS PO › Quantitative Aptitude

What approximate value will come in place of the question mark in the following expression? $64.03 \times 3.98 - (14.01)^2 + 49.99 = ?$

1. 111
2. 109
3. 110
4. 112

Correct answer: 110

Solution

Approximating gives $64.03\approx64$, $3.98\approx4$, $14.01\approx14$, and $49.99\approx50$. Then $64\times4 - 14^2 + 50 = 256 - 196 + 50 = 110$.

Related IBPS PO Quantitative Aptitude questions

• What approximate value should come in place of '?' in the following equation? 32.98% of 4399.89 - (17.03 × 22.94) = (?)² - (5.032 × 3.97) + 5.01
• What approximate value should come in place of the question mark (?) in the following equation? $23.94 \times 17.91 + 64.89 \times 59.98 = ?$
• What approximate value will come in place of the question mark (?) in the following expression? You are not expected to calculate the exact value. \(29.98\%\) of 560 + 120.11 of 39 = ?
• What approximate value comes in: 206.123 × 37.02 - 91 × 4 + 59.99 × 27.01 = ?
• \((? \div 9.97) \times 12.08 = 20.12\%\) of 1319.97. Approximate value of ?
• What approximate value should come in the place of the question mark (?) in the following equation? \[(24.98 \times 3.97) + 4.99 + 12.95 + (8.02)^2 = ?^2\]

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →