A container contains 30 litres of wine. From this container, 3 litres of wine are taken out and replaced by water. This process is repeated two more times. How much wine is now contained in the container?

12.45 liters
21.87 liters
29.50 liters
17.65 liters

Correct answer: 21.87 liters

Solution

In each operation, the fraction of wine left is $1 - \frac{3}{30} = \frac{9}{10}$. After three such operations, wine left = $30 \times \left(\frac{9}{10}\right)^3 = 21.87$ litres (approximately). Hence, the answer is 21.87 liters.

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