Exams › IBPS PO › Quantitative Aptitude
Correct answer: 150
The train’s speed is \(108 \times \frac{5}{18} = 30\) m/s. In 15 seconds, it covers \(30 \times 15 = 450\) m, which equals train length + station length = \(L + \frac{L}{2} = \frac{3L}{2}\). So \(\frac{3L}{2} = 450\), giving \(L = 300\) m and station length = 150 m.
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