Exams › IBPS PO › Quantitative Aptitude

Two equations I and II are given below. Solve them and compare the values of \(x\) and \(y\). I. \(x^2 - 16x + 63 = 0\) II. \(y^2 - 13y + 42 = 0\)

1. x < y
2. x > y
3. x ≤ y
4. x ≥ y

Correct answer: x ≥ y

Solution

Factoring gives \((x-7)(x-9)=0\), so \(x=7\) or \(9\). Also, \((y-6)(y-7)=0\), so \(y=6\) or \(7\). In every possible case, \(x\ge y\).

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