Solve the equations: I. $9x^2 - 29x + 22 = 0$ II. $y^2 - 7y + 12 = 0$ Which of the following is correct?

x > y
x ≥ y
x < y
x ≤ y

Correct answer: x < y

Solution

The first equation factors as $(9x-11)(x-2)=0$, so $x=11/9$ or $2$. The second factors as $(y-3)(y-4)=0$, so $y=3$ or $4$. Since every possible value of x is less than every possible value of y, the correct relation is $x<y$.

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